;; This example shows one way to handle the interrupts by hitting the hardware ;; directly. ;; ;; There are 6 interrupts per screen, one of which is triggered 2 HSYNCs after the start ;; of the VSYNC signal. We can use this to syncronise our interrupts. ;; ;; We first need to synchronise with the VSYNC, we can then enable our interrupts. ;; We now know exactly the order the interrupts will come and we can have 1 function for ;; each. org &4000 start: di ;; disable interrupts im 1 ;; Z80 interrupt mode (z80 calls to &0038 for each interrupt) ;; wait vsync (loop passes if VSYNC signal is high = in vsync) ld b,&f5 wait1: in a,(c) rra jr nc,wait1 ;; wait for end of vsync (loop passes when VSYNC signal is low = out of vsync) wait2: in a,(c) rra jr c,wait2 ;; now wait again for start (because we know we found the end, if we wait for VSYNC to be active ;; we know it will be the start) wait3: in a,(c) rra jr nc,wait3 ;; we are now synchronised with the start of the vsync ;; ;; next interrupt should trigger 2 HSYNCs later. ;; ;; now setup interrupts. ld a,&c3 ;; Z80 JP instruction ld hl,int1 ;; first function to call ld (&0038),a ;; write JP instruction ld (&0039),hl ;; write address ;; ;; ;; Z80 interrupt mode 1 vector is initialised ;; enable ints now. ei ;; delay loop: jp loop ;; order: ;; int1->int2 ;; int2->int3 ;; int3->int4 ;; int4->int5 ;; int5->int6 ;; int6->int1 (loop back) ;;-------------------------------------------------------------------------------------------- ;; this is synchronised to happen 2 HSYNCs after VSYNC int1: push hl ld hl,int2 ;; we handle int2 next ld (&0039),hl ;; set new interrupt vector address pop hl ei reti ;;-------------------------------------------------------------------------------------------- int2: push hl ld hl,int3 ;; we handle int3 next ld (&0039),hl ;; set new interrupt vector address pop hl ei reti ;;-------------------------------------------------------------------------------------------- int3: push hl ld hl,int4 ;; we handle int4 next ld (&0039),hl ;; set new interrupt vector address pop hl ei reti ;;-------------------------------------------------------------------------------------------- int4: push hl ld hl,int5 ;; we handle int5 next ld (&0039),hl ;; set new interrupt vector address pop hl ei reti ;;-------------------------------------------------------------------------------------------- int5: push hl ld hl,int6 ;; we handle int6 next ld (&0039),hl ;; set new interrupt vector address pop hl ei reti ;;-------------------------------------------------------------------------------------------- int6: push hl ld hl,int1 ;; we loop back to int1 next ld (&0039),hl ;; set new interrupt vector address pop hl ei reti ;;-------------------------------------------------------------------------------------------- end